3.4.57 \(\int \frac {\sqrt [3]{a+b x^3}}{x^{11} (a d-b d x^3)} \, dx\)

Optimal. Leaf size=237 \[ \frac {b^{10/3} \log \left (a d-b d x^3\right )}{3\ 2^{2/3} a^4 d}-\frac {b^{10/3} \log \left (\sqrt [3]{2} \sqrt [3]{b} x-\sqrt [3]{a+b x^3}\right )}{2^{2/3} a^4 d}-\frac {\sqrt [3]{2} b^{10/3} \tan ^{-1}\left (\frac {\frac {2 \sqrt [3]{2} \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}+1}{\sqrt {3}}\right )}{\sqrt {3} a^4 d}-\frac {169 b^3 \sqrt [3]{a+b x^3}}{140 a^4 d x}-\frac {37 b^2 \sqrt [3]{a+b x^3}}{140 a^3 d x^4}-\frac {11 b \sqrt [3]{a+b x^3}}{70 a^2 d x^7}-\frac {\sqrt [3]{a+b x^3}}{10 a d x^{10}} \]

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Rubi [C]  time = 29.21, antiderivative size = 423, normalized size of antiderivative = 1.78, number of steps used = 2, number of rules used = 2, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {511, 510} \begin {gather*} -\frac {-54 b x^3 \left (a-b x^3\right )^2 \left (2 a+3 b x^3\right ) \, _3F_2\left (\frac {2}{3},2,2;1,\frac {5}{3};\frac {2 b x^3}{b x^3+a}\right )+27 b x^3 \left (a-b x^3\right )^3 \, _4F_3\left (\frac {2}{3},2,2,2;1,1,\frac {5}{3};\frac {2 b x^3}{b x^3+a}\right )-36 a^2 b^2 x^6 \, _2F_1\left (\frac {2}{3},1;\frac {5}{3};\frac {2 b x^3}{b x^3+a}\right )+99 a^2 b^2 x^6 \, _2F_1\left (\frac {2}{3},2;\frac {5}{3};\frac {2 b x^3}{b x^3+a}\right )+90 a^2 b^2 x^6-28 a^3 b x^3 \, _2F_1\left (\frac {2}{3},1;\frac {5}{3};\frac {2 b x^3}{b x^3+a}\right )+117 a^3 b x^3 \, _2F_1\left (\frac {2}{3},2;\frac {5}{3};\frac {2 b x^3}{b x^3+a}\right )+64 a^3 b x^3+28 a^4-162 b^4 x^{12} \, _2F_1\left (\frac {2}{3},1;\frac {5}{3};\frac {2 b x^3}{b x^3+a}\right )-297 b^4 x^{12} \, _2F_1\left (\frac {2}{3},2;\frac {5}{3};\frac {2 b x^3}{b x^3+a}\right )-54 a b^3 x^9 \, _2F_1\left (\frac {2}{3},1;\frac {5}{3};\frac {2 b x^3}{b x^3+a}\right )+81 a b^3 x^9 \, _2F_1\left (\frac {2}{3},2;\frac {5}{3};\frac {2 b x^3}{b x^3+a}\right )+216 a b^3 x^9+162 b^4 x^{12}}{280 a^4 d x^{10} \left (a+b x^3\right )^{2/3}} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

Int[(a + b*x^3)^(1/3)/(x^11*(a*d - b*d*x^3)),x]

[Out]

-(28*a^4 + 64*a^3*b*x^3 + 90*a^2*b^2*x^6 + 216*a*b^3*x^9 + 162*b^4*x^12 - 28*a^3*b*x^3*Hypergeometric2F1[2/3,
1, 5/3, (2*b*x^3)/(a + b*x^3)] - 36*a^2*b^2*x^6*Hypergeometric2F1[2/3, 1, 5/3, (2*b*x^3)/(a + b*x^3)] - 54*a*b
^3*x^9*Hypergeometric2F1[2/3, 1, 5/3, (2*b*x^3)/(a + b*x^3)] - 162*b^4*x^12*Hypergeometric2F1[2/3, 1, 5/3, (2*
b*x^3)/(a + b*x^3)] + 117*a^3*b*x^3*Hypergeometric2F1[2/3, 2, 5/3, (2*b*x^3)/(a + b*x^3)] + 99*a^2*b^2*x^6*Hyp
ergeometric2F1[2/3, 2, 5/3, (2*b*x^3)/(a + b*x^3)] + 81*a*b^3*x^9*Hypergeometric2F1[2/3, 2, 5/3, (2*b*x^3)/(a
+ b*x^3)] - 297*b^4*x^12*Hypergeometric2F1[2/3, 2, 5/3, (2*b*x^3)/(a + b*x^3)] - 54*b*x^3*(a - b*x^3)^2*(2*a +
3*b*x^3)*HypergeometricPFQ[{2/3, 2, 2}, {1, 5/3}, (2*b*x^3)/(a + b*x^3)] + 27*b*x^3*(a - b*x^3)^3*Hypergeomet
ricPFQ[{2/3, 2, 2, 2}, {1, 1, 5/3}, (2*b*x^3)/(a + b*x^3)])/(280*a^4*d*x^10*(a + b*x^3)^(2/3))

Rule 510

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[(a^p*c^q
*(e*x)^(m + 1)*AppellF1[(m + 1)/n, -p, -q, 1 + (m + 1)/n, -((b*x^n)/a), -((d*x^n)/c)])/(e*(m + 1)), x] /; Free
Q[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] && (IntegerQ[p] || GtQ[a
, 0]) && (IntegerQ[q] || GtQ[c, 0])

Rule 511

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Dist[(a^IntPa
rt[p]*(a + b*x^n)^FracPart[p])/(1 + (b*x^n)/a)^FracPart[p], Int[(e*x)^m*(1 + (b*x^n)/a)^p*(c + d*x^n)^q, x], x
] /; FreeQ[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] &&  !(IntegerQ[
p] || GtQ[a, 0])

Rubi steps

\begin {align*} \int \frac {\sqrt [3]{a+b x^3}}{x^{11} \left (a d-b d x^3\right )} \, dx &=\frac {\sqrt [3]{a+b x^3} \int \frac {\sqrt [3]{1+\frac {b x^3}{a}}}{x^{11} \left (a d-b d x^3\right )} \, dx}{\sqrt [3]{1+\frac {b x^3}{a}}}\\ &=-\frac {28 a^4+64 a^3 b x^3+90 a^2 b^2 x^6+216 a b^3 x^9+162 b^4 x^{12}-28 a^3 b x^3 \, _2F_1\left (\frac {2}{3},1;\frac {5}{3};\frac {2 b x^3}{a+b x^3}\right )-36 a^2 b^2 x^6 \, _2F_1\left (\frac {2}{3},1;\frac {5}{3};\frac {2 b x^3}{a+b x^3}\right )-54 a b^3 x^9 \, _2F_1\left (\frac {2}{3},1;\frac {5}{3};\frac {2 b x^3}{a+b x^3}\right )-162 b^4 x^{12} \, _2F_1\left (\frac {2}{3},1;\frac {5}{3};\frac {2 b x^3}{a+b x^3}\right )+117 a^3 b x^3 \, _2F_1\left (\frac {2}{3},2;\frac {5}{3};\frac {2 b x^3}{a+b x^3}\right )+99 a^2 b^2 x^6 \, _2F_1\left (\frac {2}{3},2;\frac {5}{3};\frac {2 b x^3}{a+b x^3}\right )+81 a b^3 x^9 \, _2F_1\left (\frac {2}{3},2;\frac {5}{3};\frac {2 b x^3}{a+b x^3}\right )-297 b^4 x^{12} \, _2F_1\left (\frac {2}{3},2;\frac {5}{3};\frac {2 b x^3}{a+b x^3}\right )-54 b x^3 \left (a-b x^3\right )^2 \left (2 a+3 b x^3\right ) \, _3F_2\left (\frac {2}{3},2,2;1,\frac {5}{3};\frac {2 b x^3}{a+b x^3}\right )+27 b x^3 \left (a-b x^3\right )^3 \, _4F_3\left (\frac {2}{3},2,2,2;1,1,\frac {5}{3};\frac {2 b x^3}{a+b x^3}\right )}{280 a^4 d x^{10} \left (a+b x^3\right )^{2/3}}\\ \end {align*}

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Mathematica [C]  time = 5.20, size = 130, normalized size = 0.55 \begin {gather*} \frac {-14 a^4-36 a^3 b x^3-59 a^2 b^2 x^6+\frac {140 b^4 x^{12} \left (\frac {b x^3}{a}+1\right )^{2/3} \, _2F_1\left (\frac {2}{3},\frac {2}{3};\frac {5}{3};-\frac {2 b x^3}{a-b x^3}\right )}{\left (1-\frac {b x^3}{a}\right )^{2/3}}-206 a b^3 x^9-169 b^4 x^{12}}{140 a^4 d x^{10} \left (a+b x^3\right )^{2/3}} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

Integrate[(a + b*x^3)^(1/3)/(x^11*(a*d - b*d*x^3)),x]

[Out]

(-14*a^4 - 36*a^3*b*x^3 - 59*a^2*b^2*x^6 - 206*a*b^3*x^9 - 169*b^4*x^12 + (140*b^4*x^12*(1 + (b*x^3)/a)^(2/3)*
Hypergeometric2F1[2/3, 2/3, 5/3, (-2*b*x^3)/(a - b*x^3)])/(1 - (b*x^3)/a)^(2/3))/(140*a^4*d*x^10*(a + b*x^3)^(
2/3))

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IntegrateAlgebraic [A]  time = 0.57, size = 239, normalized size = 1.01 \begin {gather*} -\frac {\sqrt [3]{2} b^{10/3} \log \left (2^{2/3} \sqrt [3]{a+b x^3}-2 \sqrt [3]{b} x\right )}{3 a^4 d}-\frac {\sqrt [3]{2} b^{10/3} \tan ^{-1}\left (\frac {\sqrt {3} \sqrt [3]{b} x}{2^{2/3} \sqrt [3]{a+b x^3}+\sqrt [3]{b} x}\right )}{\sqrt {3} a^4 d}+\frac {b^{10/3} \log \left (2^{2/3} \sqrt [3]{b} x \sqrt [3]{a+b x^3}+\sqrt [3]{2} \left (a+b x^3\right )^{2/3}+2 b^{2/3} x^2\right )}{3\ 2^{2/3} a^4 d}+\frac {\sqrt [3]{a+b x^3} \left (-14 a^3-22 a^2 b x^3-37 a b^2 x^6-169 b^3 x^9\right )}{140 a^4 d x^{10}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(a + b*x^3)^(1/3)/(x^11*(a*d - b*d*x^3)),x]

[Out]

((a + b*x^3)^(1/3)*(-14*a^3 - 22*a^2*b*x^3 - 37*a*b^2*x^6 - 169*b^3*x^9))/(140*a^4*d*x^10) - (2^(1/3)*b^(10/3)
*ArcTan[(Sqrt[3]*b^(1/3)*x)/(b^(1/3)*x + 2^(2/3)*(a + b*x^3)^(1/3))])/(Sqrt[3]*a^4*d) - (2^(1/3)*b^(10/3)*Log[
-2*b^(1/3)*x + 2^(2/3)*(a + b*x^3)^(1/3)])/(3*a^4*d) + (b^(10/3)*Log[2*b^(2/3)*x^2 + 2^(2/3)*b^(1/3)*x*(a + b*
x^3)^(1/3) + 2^(1/3)*(a + b*x^3)^(2/3)])/(3*2^(2/3)*a^4*d)

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fricas [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^(1/3)/x^11/(-b*d*x^3+a*d),x, algorithm="fricas")

[Out]

Timed out

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int -\frac {{\left (b x^{3} + a\right )}^{\frac {1}{3}}}{{\left (b d x^{3} - a d\right )} x^{11}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^(1/3)/x^11/(-b*d*x^3+a*d),x, algorithm="giac")

[Out]

integrate(-(b*x^3 + a)^(1/3)/((b*d*x^3 - a*d)*x^11), x)

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maple [F]  time = 0.62, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (b \,x^{3}+a \right )^{\frac {1}{3}}}{\left (-b d \,x^{3}+a d \right ) x^{11}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^3+a)^(1/3)/x^11/(-b*d*x^3+a*d),x)

[Out]

int((b*x^3+a)^(1/3)/x^11/(-b*d*x^3+a*d),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} -\int \frac {{\left (b x^{3} + a\right )}^{\frac {1}{3}}}{{\left (b d x^{3} - a d\right )} x^{11}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^(1/3)/x^11/(-b*d*x^3+a*d),x, algorithm="maxima")

[Out]

-integrate((b*x^3 + a)^(1/3)/((b*d*x^3 - a*d)*x^11), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (b\,x^3+a\right )}^{1/3}}{x^{11}\,\left (a\,d-b\,d\,x^3\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x^3)^(1/3)/(x^11*(a*d - b*d*x^3)),x)

[Out]

int((a + b*x^3)^(1/3)/(x^11*(a*d - b*d*x^3)), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**3+a)**(1/3)/x**11/(-b*d*x**3+a*d),x)

[Out]

Timed out

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